(4x+8)=(5x^2-6x+8)=

Solution for (4x+8)=(5x^2-6x+8)= equation:

(4x+8)=(5x^2-6x+8)=

We move all terms to the left:

(4x+8)-((5x^2-6x+8))=0

We get rid of parentheses

4x-((5x^2-6x+8))+8=0


We calculate terms in parentheses: -((5x^2-6x+8)), so:

(5x^2-6x+8)

We get rid of parentheses

5x^2-6x+8

Back to the equation:

-(5x^2-6x+8)


We get rid of parentheses

-5x^2+4x+6x-8+8=0

We add all the numbers together, and all the variables

-5x^2+10x=0

a = -5; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-5)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-5}=\frac{-20}{-10}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-5}=\frac{0}{-10}
=0
$